Subtracting 2Digit Numbers with Borrowing (Regrouping)
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Right here we’ll be taught subtracting 2digit numbers with
borrowing. The subtractions with borrowing are solved stepbystep in 4
alternative ways.
When we have to subtract greater quantity from a smaller quantity in ones place, we regroup tens into ones.
Regrouping
We are able to write a 2digit quantity in several methods by regrouping tens and ones.
16 could be written as
23 could be written as
Allow us to perceive this with the assistance of an instance.
A shopkeeper sells bananas. He has 6 bunches of 10’s and 5 single bananas.
Nairitee needs to purchase 37 bananas from the shopkeeper. The shopkeeper offers her 3 bunches of 10’s and breaks one bunch of 10’s to provide 7 bananas.
The shopkeeper is now left with what number of bananas?
Column Technique
Organize the numbers in columns and subtract. In ones place, 5 is smaller than 7. We can’t take away 7 from 5. So, we break one ten into 10 ones. Now we have now, 15 ones in ones place and 5 tens in tens place.
15 ones – 7 ones = 8 We write 8 in ones place. Subtract 3 tens from 5 tens. 5 tens – 3 tens = 2 tens Write 2 in tens place. 
So, 65 – 37 = 28
Laboredout examples on subtracting 2digit numbers with borrowing:
1. Subtract 9 from 15.
Answer:
T O
1 5
– 9
Since, 5 < 9, so 9 can’t be subtracted from 5. So, 1 ten, i.e., 10 ones is borrowed from the digit 1 of tens place. Now one ten, i.e., 10 ones are added to five ones to make it 15 ones. Now 15 ones – 9 ones = 6 ones.
Due to this fact, 15 – 9 = 6
2. Subtract 37
from 65
Answer:
The numbers are positioned in column kind, with the smaller
quantity 37 written underneath the higher quantity 65.
T O
1 T → 10
6 5
– 3
7
2 8
(i) first ones are subtracted as 5 < 7 or 7 > 5. So, 7
can’t be subtracted from 5.
(ii) Now 1 ten is borrowed from 6 tens leaving 5 tens there.
(iii) 1 ten = 10 ones. So, 10 ones are added to five ones
making the sum 15 ones
(iv) 7 ones are subtracted from 15 ones i.e., 15 ones – 7
ones = 8 ones. This 8 is written in a single’s column.
(v) Now tens are subtracted. At ten’s place there are 5 tens
left. So 5 tens – 3 tens = 2 tens. So, 2 is written in ten’s column.
(vi) Due to this fact, 65 – 37 = 28.
3. Subtract 28
from 83
Answer:
The smaller quantity 28 is written underneath higher quantity 83 in
column kind and ones are subtracted first, then the tens.
T O
1 T → 10
8 3
– 2
8
5 5
(i) 3 < 8, so 1 ten, i.e., 10 ones are borrowed from 8
tens with 7tens remaining there.
(ii) Now, 1 ten + 3 = 10 + 3 = 13 ones. So, 13 ones – 8 ones
= 5 ones.
(iii) 7 tens – 2 tens = 5 tens.
Due to this fact, 83 – 28 = 55
4. Subtract 69
from 92
Answer:
The smaller quantity 69 is written underneath higher quantity 92 in
column kind and ones are subtracted first, then the tens.
T O
1 T → 10
9 2
– 6
9
2 3
(i) 10 + 2 = 12; 12 O
– 9 O = 3 O
(ii) 8 T – 6 T = 2 T
Due to this fact, 92 – 69 = 23
Subtraction with Borrowing:
5. Allow us to subtract 5 from 23.
Step I: Organize the numbers into tens and ones. 

Step II: We can’t subtract 5 from 3. So, borrow 1 ten from the tens column. 1 ten = 10 ones. Take these 10 ones to those column. This provides: 10 + 3 = 13 ones 13 – 5 = 8 

Step III: Subtract the tens. Now since we borrowed 1 ten, we’re left with 1 ten within the tens column. 
Thus, 23 – 5 = 18
6. Allow us to subtract 37 from 53.
Step I: Organize the numbers into tens and ones. 

Step II: We can’t subtract 7 from 3. So, borrow 1 ten from the tens column. 1 ten = 10 ones. Take these 10 ones to those column. This provides: 10 + 3 = 13 ones 13 – 7 = 6 

Step III: Since we have now borrowed 1 ten from 5 tens, we’re left with 4 tens. Now subtract 3 tens from 4 tens. 4 – 3 = 1 
Thus, 53 – 37 = 16
24 = 
2 
tens + 
4 
ones = 
1 
ten + 
14 
ones 
Questions and Solutions on Subtracting 2Digit Numbers with Borrowing (Regrouping):
1. Regrouping the tens and ones.
(i) 24 = 2 tens + 4 ones = 1 ten + 14 ones
1. Subtracting 1digit quantity from 2digit quantity with regrouping.
(i) 38 – 9 = _____
(ii) 62 – 7 = _____
(iii) 44 – 6 = _____
(iv) 67 – 8 = _____
(v) 75 – 7 = _____
(vi) 94 – 8 = _____
(vii) 74 – 5 = _____
(viii) 51 – 2 = _____
(ix) 95 – 6 = _____
(x) 42 – 3 = _____
(xi) 53 – 4 = _____
(xii) 62 – 4 = _____
(xiii) 67 – 8 = _____
(xiv) 32 – 5 = _____
(xv) 22 – 9 = _____
(xvi) 93 – 3 = _____
Solutions:
(i) 29
(ii) 55
(iii) 38
(iv) 59
(v) 68
(vi) 86
(vii) 69
(viii) 49
(ix) 89
(x) 39
(xi) 49
(xii) 58
(xiii) 59
(xiv) 27
(xv) 13
(xvi) 90
2. Subtracting 2digit quantity with regrouping.
(i) 80 – 17 = _____
(ii) 38 – 29 = _____
(iii) 71 – 34 = _____
(iv) 47 – 19 = _____
(v) 86 – 27 = _____
(vi) 65 – 47 = _____
(vii) 51 – 25 = _____
(viii) 62 – 37 = _____
(ix) 73 – 57 = _____
(x) 94 – 46 = _____
(xi) 46 – 28 = _____
(xii) 56 – 27 = _____
(xiii) 57 – 19 = _____
(xiv) 31 – 24 = _____
(xv) 41 – 16 = _____
(xvi) 53 – 29 = _____
Solutions:
(i) 63
(ii) 9
(iii) 37
(iv) 28
(v) 59
(vi) 18
(vii) 26
(viii) 25
(ix) 16
(x) 48
(xi) 18
(xii) 29
(xiii) 38
(xiv) 7
(xv) 25
(xvi) 24
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